What is the derivative of 3x^{-1} ?

The derivative of 3x^{-1} is -3/(x^2)

What is the first derivative of 3x^{-1} ?

The first derivative of 3x^{-1} is -3/(x^2)

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derivative of

3 x^{- 1}

- \frac{3}{x ^{2}}

Solution steps

\frac{d}{d x} (3 x^{- 1})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (x^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 3 (- 1 \cdot x^{- 1 - 1})

Simplify

3 (- 1 \cdot x^{- 1 - 1}) : - \frac{3}{x ^{2}}

= - \frac{3}{x ^{2}}

\frac{d ^{2}}{d x ^{2}} ((x^{2} + 9)^{7})

f (x) = 2 x + 3

\int u^{2} + 1 d u

ln (1 - 9 x)

x \to 1 lim (- \frac{3}{x - 1})

What is the derivative of 3x^{-1} ?
The derivative of 3x^{-1} is -3/(x^2)
What is the first derivative of 3x^{-1} ?
The first derivative of 3x^{-1} is -3/(x^2)