What is the solution for ((x^2+2y^2)dx)/(dy)=xy ?

The solution for ((x^2+2y^2)dx)/(dy)=xy is y=xsqrt(-1+c_{1)x^2},y=-xsqrt(-1+c_{1)x^2}

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((x^2+2y^2)dx)/(dy)=xy

\frac{( x ^{2} + 2 y ^{2} ) d x}{d y} = x y

y = x - 1 + c_{1} x^{2}, y = - x - 1 + c_{1} x^{2}

Solution steps

\frac{( x ^{2} + 2 y ^{2} ) d x}{d y} = x y

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y = x - 1 + c_{1} x^{2}, y = - x - 1 + c_{1} x^{2}

y = x - 1 + c_{1} x^{2}, y = - x - 1 + c_{1} x^{2}

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What is the solution for ((x^2+2y^2)dx)/(dy)=xy ?
The solution for ((x^2+2y^2)dx)/(dy)=xy is y=xsqrt(-1+c_{1)x^2},y=-xsqrt(-1+c_{1)x^2}