What is the tangent of g(x)=e^{x^5-6x},\at x=-1 ?

The tangent of g(x)=e^{x^5-6x},\at x=-1 is y=-e^5x

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tangent of g(x)=e^{x^5-6x},\at x=-1

tangent of

g (x) = e^{x^{5} - 6 x}, at x = - 1

y = - e^{5} x

Solution steps

Find the tangent point:

(- 1, e^{5})

Find the slope of

g (x) = e^{x^{5} - 6 x} : \frac{d g ( x )}{d x} = e^{x^{5} - 6 x} (5 x^{4} - 6)

Compute the slope of

g (x) = e^{x^{5} - 6 x}

x = - 1 : m = - e^{5}

Find the line with slope m=

- e^{5}

and passing through

(- 1, e^{5}) : y = - e^{5} x

y = - e^{5} x

\frac{2 x ^{2} + 6 x + 8}{x}

\int \frac{u}{2} d u

\frac{\partial}{\partial x} (x^{2} sin (y) cos (y))

\frac{d}{d v} (u^{2} - v^{2})

\int_{0}^{2} \frac{1}{x + 2} d x

What is the tangent of g(x)=e^{x^5-6x},\at x=-1 ?
The tangent of g(x)=e^{x^5-6x},\at x=-1 is y=-e^5x