What is the integral of 9x^2-24x-36 ?

The integral of 9x^2-24x-36 is 3x^3-12x^2-36x+C

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integral of 9x^2-24x-36

\int 9 x^{2} - 24 x - 36 d x

3 x^{3} - 12 x^{2} - 36 x + C

Solution steps

\int 9 x^{2} - 24 x - 36 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 9 x^{2} d x - \int 24 x d x - \int 36 d x

\int 9 x^{2} d x = 3 x^{3}

\int 24 x d x = 12 x^{2}

\int 36 d x = 36 x

= 3 x^{3} - 12 x^{2} - 36 x

Add a constant to the solution

= 3 x^{3} - 12 x^{2} - 36 x + C

\frac{d}{d x} (cos (1 - 4 x))

f (x) = \frac{3 - ( \frac{1}{x ^{2}} )}{x + 4}

\int e^{- s t} cos (t) d t

t y^{^{'}} = 2

\frac{d}{d x} (sec^{2} (x))

What is the integral of 9x^2-24x-36 ?
The integral of 9x^2-24x-36 is 3x^3-12x^2-36x+C