What is the first (tan(2x))^' ?

The first (tan(2x))^' is sec^2(2x)*2

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(tan(2x))^'

(tan (2 x))^{^{'}}

sec^{2} (2 x) \cdot 2

Solution steps

(tan (2 x))^{'}

Apply the chain rule:

sec^{2} (2 x) (2 x)^{'}

= sec^{2} (2 x) (2 x)^{'}

(2 x)^{'} = 2

= sec^{2} (2 x) \cdot 2

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