What is the sum from n=2 to infinity of e^{5-2n} ?

The sum from n=2 to infinity of e^{5-2n} is converges

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sum from n=2 to infinity of e^{5-2n}

n = 2 \sum \infty e^{5 - 2 n}

converges

Solution steps

n = 2 \sum \infty e^{5 - 2 n}

Apply Series Ratio Test:

converges

= converges

x^{2} y^{^{'}} + y^{2} - x y = 0

\int \frac{x - 3}{x + 4} d x

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\frac{1}{x - 6}

What is the sum from n=2 to infinity of e^{5-2n} ?
The sum from n=2 to infinity of e^{5-2n} is converges