What is the derivative of ax^n ?

The derivative of ax^n is anx^{n-1}

What is the first derivative of ax^n ?

The first derivative of ax^n is anx^{n-1}

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\frac{d}{d x} (a x^{n})

an x^{n - 1}

Solution steps

\frac{d}{d x} (a x^{n})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= a \frac{d}{d x} (x^{n})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= an x^{n - 1}

\frac{d}{d x} (\frac{1}{x ^{4} + 1})

\int (8^{x} - sec^{2} (x)) d x

x^{2} y^{^{''}} - 2 x y^{^{'}} - 40 y = x^{4}

\int \frac{1}{t ^{2} 225 - t ^{2}} d t

x \to 1 + lim (- 6)

What is the derivative of ax^n ?
The derivative of ax^n is anx^{n-1}
What is the first derivative of ax^n ?
The first derivative of ax^n is anx^{n-1}