What is the integral from 3 to 5 of (x^2)/8 ?

The integral from 3 to 5 of (x^2)/8 is 49/12

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integral from 3 to 5 of (x^2)/8

\int_{3}^{5} \frac{x ^{2}}{8} d x

\frac{49}{12}

Decimal Notation

4.08333 \dots

Solution steps

\int_{3}^{5} \frac{x ^{2}}{8} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{8} \cdot \int_{3}^{5} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{3}^{5}

= \frac{1}{8} [\frac{x ^{3}}{3}]_{3}^{5}

Compute the boundaries:

\frac{98}{3}

= \frac{1}{8} \cdot \frac{98}{3}

Simplify

= \frac{49}{12}

n = 1 \sum \infty \frac{n}{1000 n + 1}

\frac{d}{d x} (3^{x} x^{3})

\frac{d}{d x} (1 - x^{3})

\frac{d ^{4}}{d x ^{4}} (13 e^{x^{2}})

\frac{x ^{2} - 100}{x - 10}

What is the integral from 3 to 5 of (x^2)/8 ?
The integral from 3 to 5 of (x^2)/8 is 49/12