What is the derivative of (x^3+1^4) ?

The derivative of (x^3+1^4) is 12x^2(x^3+1)^3

What is the first derivative of (x^3+1^4) ?

The first derivative of (x^3+1^4) is 12x^2(x^3+1)^3

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\frac{d}{d x} ((x^{3} + 1)^{4})

12 x^{2} (x^{3} + 1)^{3}

Solution steps

\frac{d}{d x} ((x^{3} + 1)^{4})

Apply the chain rule:

4 (x^{3} + 1)^{3} \frac{d}{d x} (x^{3} + 1)

= 4 (x^{3} + 1)^{3} \frac{d}{d x} (x^{3} + 1)

\frac{d}{d x} (x^{3} + 1) = 3 x^{2}

= 4 (x^{3} + 1)^{3} \cdot 3 x^{2}

Simplify

= 12 x^{2} (x^{3} + 1)^{3}

\int x^{2} - 7 x + 2 d x

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\frac{\partial}{\partial x} (ln (x) - 1)

\int sec (x) - cos (x) d x

What is the derivative of (x^3+1^4) ?
The derivative of (x^3+1^4) is 12x^2(x^3+1)^3
What is the first derivative of (x^3+1^4) ?
The first derivative of (x^3+1^4) is 12x^2(x^3+1)^3