What is the tangent of-6sqrt(x),\at x=4 ?

The tangent of-6sqrt(x),\at x=4 is y=-3/2 x-6

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tangent of-6sqrt(x),\at x=4

tangent of

- 6 x, at x = 4

y = - \frac{3}{2} x - 6

Solution steps

Find the tangent point:

(4, - 12)

Find the slope of

y = - 6 x : \frac{d y}{d x} = - \frac{3}{x}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{3}{2}

Find the line with slope m=

- \frac{3}{2}

and passing through

(4, - 12) : y = - \frac{3}{2} x - 6

y = - \frac{3}{2} x - 6

\int y sin (x) y d x

\int \frac{e ^{x}}{e ^{3 x} - 2 e ^{2 x} + e ^{x} - 2} d x

\frac{\partial}{\partial y} (6 x y^{2})

\int 4 x ln (7 x) d x

\frac{\partial}{\partial x} (ln (2 x + y + 1))

What is the tangent of-6sqrt(x),\at x=4 ?
The tangent of-6sqrt(x),\at x=4 is y=-3/2 x-6