What is the derivative of (16/(x^3)) ?

The derivative of (16/(x^3)) is -(48)/(x^4)

What is the first derivative of (16/(x^3)) ?

The first derivative of (16/(x^3)) is -(48)/(x^4)

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\frac{d}{d x} (\frac{16}{x ^{3}})

- \frac{48}{x ^{4}}

Solution steps

\frac{d}{d x} (\frac{16}{x ^{3}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 16 \frac{d}{d x} (\frac{1}{x ^{3}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 16 \frac{d}{d x} (x^{- 3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 16 (- 3 x^{- 3 - 1})

Simplify

16 (- 3 x^{- 3 - 1}) : - \frac{48}{x ^{4}}

= - \frac{48}{x ^{4}}

5 y^{^{'}} + y = - 3

f (x) = 3 x^{4} - 8 x^{3} + 2

\frac{d}{d x} (5 e^{- 2 x} sin (3 x))

(1 + x)^{- \frac{5}{3}}

\frac{\partial}{\partial x} (ln (x y))

What is the derivative of (16/(x^3)) ?
The derivative of (16/(x^3)) is -(48)/(x^4)
What is the first derivative of (16/(x^3)) ?
The first derivative of (16/(x^3)) is -(48)/(x^4)