What is the derivative of 11-x+4ln(2x-1) ?

The derivative of 11-x+4ln(2x-1) is 8/(2x-1)-1

What is the first derivative of 11-x+4ln(2x-1) ?

The first derivative of 11-x+4ln(2x-1) is 8/(2x-1)-1

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\frac{d}{d x} (11 - x + 4 ln (2 x - 1))

\frac{8}{2 x - 1} - 1

Solution steps

\frac{d}{d x} (11 - x + 4 ln (2 x - 1))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (11) - \frac{d x}{d x} + \frac{d}{d x} (4 ln (2 x - 1))

\frac{d}{d x} (11) = 0

\frac{d x}{d x} = 1

\frac{d}{d x} (4 ln (2 x - 1)) = \frac{8}{2 x - 1}

= 0 - 1 + \frac{8}{2 x - 1}

Simplify

= \frac{8}{2 x - 1} - 1

x \to 0 lim (\frac{∣ x - 4 ∣}{x - 4})

\frac{d}{d x} (x + y + 1)

f (x) = 2 e^{2 e^{x} + x}

\frac{3}{y ^{4}}

y^{^{''}} + 2 y^{^{'}} + y = 2^{- t}

What is the derivative of 11-x+4ln(2x-1) ?
The derivative of 11-x+4ln(2x-1) is 8/(2x-1)-1
What is the first derivative of 11-x+4ln(2x-1) ?
The first derivative of 11-x+4ln(2x-1) is 8/(2x-1)-1