What is the integral of xe^{0.2x} ?

The integral of xe^{0.2x} is 5e^{0.2x}x-25e^{0.2x}+C

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integral of xe^{0.2x}

\int x e^{0.2 x} d x

5 e^{0.2 x} x - 25 e^{0.2 x} + C

Solution steps

\int x e^{0.2 x} d x

Apply Integration By Parts

: 5 e^{0.2 x} x - \int 5 e^{0.2 x} d x

= 5 e^{0.2 x} x - \int 5 e^{0.2 x} d x

\int 5 e^{0.2 x} d x = 25 e^{0.2 x}

= 5 e^{0.2 x} x - 25 e^{0.2 x}

Add a constant to the solution

= 5 e^{0.2 x} x - 25 e^{0.2 x} + C

f (x) = x^{3} + 3 x

x^{\frac{5}{7}}

f (x) = \frac{x + 9}{x - 9}

t^{2} y^{^{''}} - 5 t y^{^{'}} + 9 y = 0

x cos (3 x)

What is the integral of xe^{0.2x} ?
The integral of xe^{0.2x} is 5e^{0.2x}x-25e^{0.2x}+C