What is the derivative of y=sqrt(4+3x) ?

The derivative of y=sqrt(4+3x) is 3/(2sqrt(4+3x))

What is the first derivative of y=sqrt(4+3x) ?

The first derivative of y=sqrt(4+3x) is 3/(2sqrt(4+3x))

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derivative of

y = 4 + 3 x

\frac{3}{2 4 + 3 x}

Solution steps

\frac{d}{d x} (4 + 3 x)

Apply the chain rule:

\frac{1}{2 4 + 3 x} \frac{d}{d x} (4 + 3 x)

= \frac{1}{2 4 + 3 x} \frac{d}{d x} (4 + 3 x)

\frac{d}{d x} (4 + 3 x) = 3

= \frac{1}{2 4 + 3 x} \cdot 3

Simplify

\frac{1}{2 4 + 3 x} \cdot 3 : \frac{3}{2 4 + 3 x}

= \frac{3}{2 4 + 3 x}

\frac{d}{d x} ((ln (x))^{l n (x)})

\int_{0}^{1} x^{3} e^{x} d x

x \to 25 lim (2 x + 2 x)

\int - 9 cos (x) d x

x \to 3 lim (\frac{x - 1}{x ^{2} - 2})

What is the derivative of y=sqrt(4+3x) ?
The derivative of y=sqrt(4+3x) is 3/(2sqrt(4+3x))
What is the first derivative of y=sqrt(4+3x) ?
The first derivative of y=sqrt(4+3x) is 3/(2sqrt(4+3x))