What is the tangent of f(x)=sin(sin(x)),\at x=3pi,0 ?

The tangent of f(x)=sin(sin(x)),\at x=3pi,0 is y=-x+3pi

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=sin(sin(x)),\at x=3pi,0

tangent of

f (x) = sin (sin (x)), at x = 3 π, 0

y = - x + 3 π

Solution steps

Find the tangent point:

(3 π, 0)

Find the slope of

f (x) = sin (sin (x)) : \frac{df ( x )}{d x} = cos (sin (x)) cos (x)

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 1

Find the line with slope m=

- 1

and passing through

(3 π, 0) : y = - x + 3 π

y = - x + 3 π

a^{x}

(3 x^{2} y^{2} + y) d x + (2 x^{3} y + x) d y = 0

y = e^{x}, y = e^{- 4 x}, x = ln (3)

\int x x + 4 d x

\int_{0}^{\frac{π}{6}} cos^{3} (x) d x

What is the tangent of f(x)=sin(sin(x)),\at x=3pi,0 ?
The tangent of f(x)=sin(sin(x)),\at x=3pi,0 is y=-x+3pi