What is area y=e^x,y=e^{-4x},x=ln(3) ?

The answer to area y=e^x,y=e^{-4x},x=ln(3) is 142/81

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area y=e^x,y=e^{-4x},x=ln(3)

area

y = e^{x}, y = e^{- 4 x}, x = ln (3)

\frac{142}{81}

Decimal

1.75308 \dots

Solution steps

Apply the area formula:

\int_{0}^{l n (3)} e^{x} - e^{- 4 x} d x

Solve

\int_{0}^{l n (3)} e^{x} - e^{- 4 x} d x : \frac{142}{81}

The area is:

= \frac{142}{81}

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What is area y=e^x,y=e^{-4x},x=ln(3) ?
The answer to area y=e^x,y=e^{-4x},x=ln(3) is 142/81