What is the tangent of f(x)=8+5x^2-2x^3,(2,12) ?

The tangent of f(x)=8+5x^2-2x^3,(2,12) is y=-4x+20

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tangent of f(x)=8+5x^2-2x^3,(2,12)

tangent of

f (x) = 8 + 5 x^{2} - 2 x^{3}, (2, 12)

y = - 4 x + 20

Solution steps

Find the slope of

f (x) = 8 + 5 x^{2} - 2 x^{3} : \frac{df ( x )}{d x} = - 6 x^{2} + 10 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 4

Find the line with slope m=

- 4

and passing through

(2, 12) : y = - 4 x + 20

y = - 4 x + 20

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\frac{d}{d x} (- (x + 1) (x - 1)^{2})

f (x) = (\frac{x + 3}{x - 3})^{5}

\int (x + \frac{1}{x ^{3}}) d x

What is the tangent of f(x)=8+5x^2-2x^3,(2,12) ?
The tangent of f(x)=8+5x^2-2x^3,(2,12) is y=-4x+20