What is the derivative of y=sqrt(x)(x-8) ?

The derivative of y=sqrt(x)(x-8) is (3x-8)/(2sqrt(x))

What is the first derivative of y=sqrt(x)(x-8) ?

The first derivative of y=sqrt(x)(x-8) is (3x-8)/(2sqrt(x))

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derivative of

y = x (x - 8)

\frac{3 x - 8}{2 x}

Solution steps

\frac{d}{d x} (x (x - 8))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = x - 8

= \frac{d}{d x} (x) (x - 8) + \frac{d}{d x} (x - 8) x

\frac{d}{d x} (x) = \frac{1}{2 x}

\frac{d}{d x} (x - 8) = 1

= \frac{1}{2 x} (x - 8) + 1 \cdot x

Simplify

\frac{1}{2 x} (x - 8) + 1 \cdot x : \frac{3 x - 8}{2 x}

= \frac{3 x - 8}{2 x}

2^{3 x + 1}

\frac{d}{d r} (\frac{r}{r ^{2} + 1})

f (x) = x \cdot 5^{x}, at x = 1

\int 1 - x d x

y^{^{''}} - 3 y^{^{'}} + 2 y = 2 e^{3} t

What is the derivative of y=sqrt(x)(x-8) ?
The derivative of y=sqrt(x)(x-8) is (3x-8)/(2sqrt(x))
What is the first derivative of y=sqrt(x)(x-8) ?
The first derivative of y=sqrt(x)(x-8) is (3x-8)/(2sqrt(x))