y^{''}-3y^'+2y=2e^3t

解答

y^{^{''}} - 3 y^{^{'}} + 2 y = 2 e^{3} t

y = c_{1} e^{2 t} + c_{2} e^{t} + e^{3} t + \frac{3 e ^{3}}{2}

求解步骤

y^{''} (t) - 3 y^{'} (t) + 2 y = 2 e^{3} t

求解线性方程:

y = c_{1} e^{2 t} + c_{2} e^{t} + e^{3} t + \frac{3 e ^{3}}{2}

y = c_{1} e^{2 t} + c_{2} e^{t} + e^{3} t + \frac{3 e ^{3}}{2}

s l o p e (- 1, 3), (13, 1)

\int \frac{tan ( x )}{cos ^{2} ( x )} d x

\frac{d}{d x} (\frac{6 x - 1}{4 x + 3})

\frac{d}{d x} (\frac{1}{( x + 8 ) ^{2}})

\int 8 csc (x) d x