What is the derivative of 1/(2+t) ?

The derivative of 1/(2+t) is -1/((2+t)^2)

What is the first derivative of 1/(2+t) ?

The first derivative of 1/(2+t) is -1/((2+t)^2)

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derivative of

\frac{1}{2 + t}

- \frac{1}{( 2 + t ) ^{2}}

Solution steps

\frac{d}{d t} (\frac{1}{2 + t})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d t} ((2 + t)^{- 1})

Apply the chain rule:

- \frac{1}{( 2 + t ) ^{2}} \frac{d}{d t} (2 + t)

= - \frac{1}{( 2 + t ) ^{2}} \frac{d}{d t} (2 + t)

\frac{d}{d t} (2 + t) = 1

= - \frac{1}{( 2 + t ) ^{2}} \cdot 1

Simplify

= - \frac{1}{( 2 + t ) ^{2}}

\int 8 csc (x) d x

f (x) = 5 x + 39, at x = 5

\frac{x}{5 + x ^{2}}

\frac{20}{- 5 s + 3}

\frac{d}{d x} (\frac{1}{x} + 2 x)

What is the derivative of 1/(2+t) ?
The derivative of 1/(2+t) is -1/((2+t)^2)
What is the first derivative of 1/(2+t) ?
The first derivative of 1/(2+t) is -1/((2+t)^2)