What is the integral of 8csc(x) ?

The integral of 8csc(x) is 8ln|tan(x/2)|+C

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integral of 8csc(x)

\int 8 csc (x) d x

8 ln tan (\frac{x}{2}) + C

Solution steps

\int 8 csc (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 8 \cdot \int csc (x) d x

Apply u-substitution

: \int \frac{1}{u} d u

= 8 \cdot \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= 8 ln ∣ u ∣

Substitute back

u = tan (\frac{x}{2})

= 8 ln tan (\frac{x}{2})

Add a constant to the solution

= 8 ln tan (\frac{x}{2}) + C

f (x) = 5 x + 39, at x = 5

\frac{x}{5 + x ^{2}}

\frac{20}{- 5 s + 3}

\frac{d}{d x} (\frac{1}{x} + 2 x)

sin (t - \frac{π}{2})