What is laplacetransform sin(t-pi/2) ?

The answer to laplacetransform sin(t-pi/2) is -s/(s^2+1)

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laplacetransform sin(t-pi/2)

laplace transform

sin (t - \frac{π}{2})

- \frac{s}{s ^{2} + 1}

Solution steps

L {sin (t - \frac{π}{2})}

Use Laplace Transform table:

L {sin (a t + b)} = \frac{s \cdot sin ( b ) + a \cdot cos ( b )}{s ^{2} + a ^{2}}

L {sin (t - \frac{π}{2})} = \frac{s sin ( - \frac{π}{2} ) + 1 \cdot cos ( - \frac{π}{2} )}{s ^{2} + 1 ^{2}}

= \frac{s sin ( - \frac{π}{2} ) + 1 \cdot cos ( - \frac{π}{2} )}{s ^{2} + 1 ^{2}}

= - \frac{s}{s ^{2} + 1}

f (x) = 3 - 4 x

n = 0 \sum \infty \frac{1}{3} \cdot (\frac{1}{3})^{n}

\int x^{2} sin (z x) d x

y^{^{'}} + \frac{4}{x} y = x^{9}

x \to \infty lim (arctan (\frac{( 1 - x ^{2} )}{( 1 + x )}))

What is laplacetransform sin(t-pi/2) ?
The answer to laplacetransform sin(t-pi/2) is -s/(s^2+1)