What is the tangent of f(x)=5x-2sqrt(x),(1,3) ?

The tangent of f(x)=5x-2sqrt(x),(1,3) is y=4x-1

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tangent of f(x)=5x-2sqrt(x),(1,3)

tangent of

f (x) = 5 x - 2 x, (1, 3)

y = 4 x - 1

Solution steps

Find the slope of

f (x) = 5 x - 2 x : \frac{df ( x )}{d x} = 5 - \frac{1}{x}

Compute the slope of

f (x) = 5 x - 2 x

(1, 3) : m = 4

Find the line with slope m=

4

and passing through

(1, 3) : y = 4 x - 1

y = 4 x - 1

\frac{d y}{d x}, y = x^{3} + 7

\frac{d}{d x} (- x^{3})

\int cot (5 x) d x

- \frac{12}{s ^{2} - 5}

\int 17 θ sec^{2} (θ) d θ

What is the tangent of f(x)=5x-2sqrt(x),(1,3) ?
The tangent of f(x)=5x-2sqrt(x),(1,3) is y=4x-1