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Popular >

2sec(2t)2t*y^'=1

Solution

2 sec (2 t) 2 t \cdot y^{^{'}} = 1

Solution

y = \frac{1}{4} Ci (2 t) + c_{1}

Solution steps

2 sec (2 t) 2 t \cdot y^{'} (t) = 1

Isolate

y^{'} (t) : y^{'} (t) = \frac{1}{4 t sec ( 2 t )}

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int \frac{1}{4 t sec ( 2 t )} d t

y = \frac{1}{4} Ci (2 t) + c_{1}

Popular Examples

area y=3x^3,y=75x area

y = 3 x^{3}, y = 75 x

derivative of sqrt(x-3)derivative of

x - 3

derivative of 7pir^2 derivative of

7 π r^{2}

tangent of x^2-7 tangent of

x^{2} - 7

(y^')/(sqrt(y))=6x^2

\frac{y ^{^{'}}}{y} = 6 x^{2}

Frequently Asked Questions (FAQ)

What is the solution for 2sec(2t)2t*y^'=1 ?
The solution for 2sec(2t)2t*y^'=1 is y= 1/4 \Ci(2t)+c_{1}