What is the derivative of y=e^{7x+1} ?

The derivative of y=e^{7x+1} is e^{7x+1}*7

What is the first derivative of y=e^{7x+1} ?

The first derivative of y=e^{7x+1} is e^{7x+1}*7

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derivative of

y = e^{7 x + 1}

e^{7 x + 1} \cdot 7

Solution steps

\frac{d}{d x} (e^{7 x + 1})

Apply the chain rule:

e^{7 x + 1} \frac{d}{d x} (7 x + 1)

= e^{7 x + 1} \frac{d}{d x} (7 x + 1)

\frac{d}{d x} (7 x + 1) = 7

= e^{7 x + 1} \cdot 7

\int x^{2} \cdot (1 + 2 x^{3})^{5} d x

\frac{d}{d x} (9 x - \frac{1}{x})

f (x) = 4 x^{5} ln (x)

e^{20 t}

y^{^{'}} = \frac{( x y ^{2} )}{( 1 + x ^{2} )}

What is the derivative of y=e^{7x+1} ?
The derivative of y=e^{7x+1} is e^{7x+1}*7
What is the first derivative of y=e^{7x+1} ?
The first derivative of y=e^{7x+1} is e^{7x+1}*7