What is the integral from 0 to 2 of t^2 ?

The integral from 0 to 2 of t^2 is 8/3

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integral from 0 to 2 of t^2

\int_{0}^{2} t^{2} d t

\frac{8}{3}

Decimal Notation

2.66666 \dots

Solution steps

\int_{0}^{2} t^{2} d t

Apply the Power Rule

: [\frac{t ^{3}}{3}]_{0}^{2}

= [\frac{t ^{3}}{3}]_{0}^{2}

Compute the boundaries:

\frac{8}{3}

= \frac{8}{3}

\frac{d}{d t} (\frac{4}{3} π t^{3})

\frac{\partial}{\partial t} (6 e^{x} t + x t)

\frac{d y}{d x} = \frac{x ^{7} - 2 y}{x}

\int_{0}^{2} x^{3} - 2 x^{2} d x

\frac{d}{d x} (\frac{3 x}{x + 2})

What is the integral from 0 to 2 of t^2 ?
The integral from 0 to 2 of t^2 is 8/3