What is the derivative of h(x)=(-3x+2)^4(-2x+3)^3 ?

The derivative of h(x)=(-3x+2)^4(-2x+3)^3 is -12(-3x+2)^3(-2x+3)^3-6(-2x+3)^2(-3x+2)^4

What is the first derivative of h(x)=(-3x+2)^4(-2x+3)^3 ?

The first derivative of h(x)=(-3x+2)^4(-2x+3)^3 is -12(-3x+2)^3(-2x+3)^3-6(-2x+3)^2(-3x+2)^4

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derivative of

h (x) = (- 3 x + 2)^{4} (- 2 x + 3)^{3}

- 12 (- 3 x + 2)^{3} (- 2 x + 3)^{3} - 6 (- 2 x + 3)^{2} (- 3 x + 2)^{4}

Solution steps

\frac{d}{d x} ((- 3 x + 2)^{4} (- 2 x + 3)^{3})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = (- 3 x + 2)^{4}, g = (- 2 x + 3)^{3}

= \frac{d}{d x} ((- 3 x + 2)^{4}) (- 2 x + 3)^{3} + \frac{d}{d x} ((- 2 x + 3)^{3}) (- 3 x + 2)^{4}

\frac{d}{d x} ((- 3 x + 2)^{4}) = - 12 (- 3 x + 2)^{3}

\frac{d}{d x} ((- 2 x + 3)^{3}) = - 6 (- 2 x + 3)^{2}

= (- 12 (- 3 x + 2)^{3}) (- 2 x + 3)^{3} + (- 6 (- 2 x + 3)^{2}) (- 3 x + 2)^{4}

Simplify

= - 12 (- 3 x + 2)^{3} (- 2 x + 3)^{3} - 6 (- 2 x + 3)^{2} (- 3 x + 2)^{4}

\int t^{2} sin (β) t d t

\int csc (x) cot (x) d x

f (x) = - 8 x sin (4 x^{2} + 1)

\frac{d}{d x} (- f (x) sin (x) + g (x) cos (x))

What is the derivative of h(x)=(-3x+2)^4(-2x+3)^3 ?
The derivative of h(x)=(-3x+2)^4(-2x+3)^3 is -12(-3x+2)^3(-2x+3)^3-6(-2x+3)^2(-3x+2)^4
What is the first derivative of h(x)=(-3x+2)^4(-2x+3)^3 ?
The first derivative of h(x)=(-3x+2)^4(-2x+3)^3 is -12(-3x+2)^3(-2x+3)^3-6(-2x+3)^2(-3x+2)^4