What is the integral of e^x(x^2-2x+2) ?

The integral of e^x(x^2-2x+2) is e^xx^2-4e^xx+6e^x+C

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integral of e^x(x^2-2x+2)

\int e^{x} (x^{2} - 2 x + 2) d x

e^{x} x^{2} - 4 e^{x} x + 6 e^{x} + C

Solution steps

\int e^{x} (x^{2} - 2 x + 2) d x

Expand

e^{x} (x^{2} - 2 x + 2) : e^{x} x^{2} - 2 e^{x} x + 2 e^{x}

= \int e^{x} x^{2} - 2 e^{x} x + 2 e^{x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int e^{x} x^{2} d x - \int 2 e^{x} x d x + \int 2 e^{x} d x

\int e^{x} x^{2} d x = x^{2} e^{x} - 2 (e^{x} x - e^{x})

\int 2 e^{x} x d x = 2 (e^{x} x - e^{x})

\int 2 e^{x} d x = 2 e^{x}

= x^{2} e^{x} - 2 (e^{x} x - e^{x}) - 2 (e^{x} x - e^{x}) + 2 e^{x}

Simplify

x^{2} e^{x} - 2 (e^{x} x - e^{x}) - 2 (e^{x} x - e^{x}) + 2 e^{x} : e^{x} x^{2} - 4 e^{x} x + 6 e^{x}

= e^{x} x^{2} - 4 e^{x} x + 6 e^{x}

Add a constant to the solution

= e^{x} x^{2} - 4 e^{x} x + 6 e^{x} + C

arctan (x^{4})

y = \frac{1}{x + 1} + 1

\frac{d}{d x} (sin (1 + x^{2}))

y^{^{''}} + 2 y^{^{'}} + 5 y = e^{- x} sec (2 x)

\frac{d ^{2}}{d x ^{2}} (6 csc (x))

What is the integral of e^x(x^2-2x+2) ?
The integral of e^x(x^2-2x+2) is e^xx^2-4e^xx+6e^x+C