What is (\partial)/(\partial y)(x-x^2y^2) ?

The answer to (\partial)/(\partial y)(x-x^2y^2) is -2x^2y

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(\partial)/(\partial y)(x-x^2y^2)

\frac{\partial}{\partial y} (x - x^{2} y^{2})

- 2 x^{2} y

Solution steps

\frac{\partial}{\partial y} (x - x^{2} y^{2})

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (x) - \frac{\partial}{\partial y} (x^{2} y^{2})

\frac{\partial}{\partial y} (x) = 0

\frac{\partial}{\partial y} (x^{2} y^{2}) = 2 x^{2} y

= 0 - 2 x^{2} y

Simplify

= - 2 x^{2} y

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What is (\partial)/(\partial y)(x-x^2y^2) ?
The answer to (\partial)/(\partial y)(x-x^2y^2) is -2x^2y