What is the solution for y^'=-sin(x)-sin(x)y,y(0)=8 ?

The solution for y^'=-sin(x)-sin(x)y,y(0)=8 is y=9e^{cos(x)-1}-1

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y^'=-sin(x)-sin(x)y,y(0)=8

y^{^{'}} = - sin (x) - sin (x) y, y (0) = 8

y = 9 e^{c o s (x) - 1} - 1

Solution steps

y^{'} (x) = - sin (x) - sin (x) y

Solve separable ODE:

y = 9 e^{c o s (x) - 1} - 1

y = 9 e^{c o s (x) - 1} - 1

x \to 0 + lim (\frac{1}{e ^{x} - 1})

y^{^{''}} + 16 y = sec^{2} (4 x)

\frac{x ^{3}}{6}

3 x y - 2 π cos (y) = 20 π, (6, π)

\int x^{2} sin (3 x + 2) d x

What is the solution for y^'=-sin(x)-sin(x)y,y(0)=8 ?
The solution for y^'=-sin(x)-sin(x)y,y(0)=8 is y=9e^{cos(x)-1}-1