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Popular >

d/(dt)(acos(2t)+bsin(2t))

Solution

\frac{d}{d t} (a cos (2 t) + b sin (2 t))

Solution

- 2 a sin (2 t) + b cos (2 t) \cdot 2

Solution steps

\frac{d}{d t} (a cos (2 t) + b sin (2 t))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (a cos (2 t)) + \frac{d}{d t} (b sin (2 t))

\frac{d}{d t} (a cos (2 t)) = - 2 a sin (2 t)

\frac{d}{d t} (b sin (2 t)) = b cos (2 t) \cdot 2

= - 2 a sin (2 t) + b cos (2 t) \cdot 2

Popular Examples

tangent of f(x)=(25-0.075x)x,\at x=100 tangent of

f (x) = (25 - 0.075 x) x, at x = 100

integral of (4x^2-14x-6)/(x^3-2x^2-3x)

\int \frac{4 x ^{2} - 14 x - 6}{x ^{3} - 2 x ^{2} - 3 x} d x

sum from n=1 to infinity of 1-cos(1/n)

n = 1 \sum \infty 1 - cos (\frac{1}{n})

limit as x approaches+1+of (x-1)/(x-1)

x \to + 1 + lim (\frac{x - 1}{x - 1})

((y^'-e^{-t}+6))/y =-6

\frac{( y ^{^{'}} - e ^{- t} + 6 )}{y} = - 6

Frequently Asked Questions (FAQ)

What is the d/(dt)(acos(2t)+bsin(2t)) ?
The d/(dt)(acos(2t)+bsin(2t)) is -2asin(2t)+bcos(2t)*2
What is the first d/(dt)(acos(2t)+bsin(2t)) ?
The first d/(dt)(acos(2t)+bsin(2t)) is -2asin(2t)+bcos(2t)*2