What is (\partial)/(\partial x)(sin(xy)+xcos(y)) ?

The answer to (\partial)/(\partial x)(sin(xy)+xcos(y)) is cos(xy)y+cos(y)

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(\partial)/(\partial x)(sin(xy)+xcos(y))

\frac{\partial}{\partial x} (sin (x y) + x cos (y))

cos (x y) y + cos (y)

Solution steps

\frac{\partial}{\partial x} (sin (x y) + x cos (y))

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (sin (x y)) + \frac{\partial}{\partial x} (x cos (y))

\frac{\partial}{\partial x} (sin (x y)) = cos (x y) y

\frac{\partial}{\partial x} (x cos (y)) = cos (y)

= cos (x y) y + cos (y)

\frac{d}{d x} (\frac{x - x}{x ^{\frac{1}{9}}})

y = 2 x + 5, y = 14 - x^{2}, (- 1, 2)

y = x^{\frac{1}{2}}, y = x^{2}

\int_{1}^{e} \frac{1 - ln ( x )}{x} d x

\frac{\partial}{\partial b} (m x + b)

What is (\partial)/(\partial x)(sin(xy)+xcos(y)) ?
The answer to (\partial)/(\partial x)(sin(xy)+xcos(y)) is cos(xy)y+cos(y)