What is the derivative of y=2+sqrt(x-7) ?

The derivative of y=2+sqrt(x-7) is 1/(2sqrt(x-7))

What is the first derivative of y=2+sqrt(x-7) ?

The first derivative of y=2+sqrt(x-7) is 1/(2sqrt(x-7))

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derivative of

y = 2 + x - 7

\frac{1}{2 x - 7}

Solution steps

\frac{d}{d x} (2 + x - 7)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2) + \frac{d}{d x} (x - 7)

\frac{d}{d x} (2) = 0

\frac{d}{d x} (x - 7) = \frac{1}{2 x - 7}

= 0 + \frac{1}{2 x - 7}

Simplify

= \frac{1}{2 x - 7}

x \to \infty lim (e^{\frac{1}{x} l n (2^{x} + 3^{x} + 5^{x})})

\frac{d}{d x} (cos^{2} (1 - 2 x))

x y + y^{^{'}} = 166 x

(2 x y + 2 y^{2}) d x + (x^{2} + 4 x y) d y = 0, y (1) = 1

\int \frac{1}{x ^{2}} + 1 d x

What is the derivative of y=2+sqrt(x-7) ?
The derivative of y=2+sqrt(x-7) is 1/(2sqrt(x-7))
What is the first derivative of y=2+sqrt(x-7) ?
The first derivative of y=2+sqrt(x-7) is 1/(2sqrt(x-7))