What is the integral of x^{(-3)/2} ?

The integral of x^{(-3)/2} is -2/(x^{1/2)}+C

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integral of x^{(-3)/2}

\int x^{\frac{- 3}{2}} d x

- \frac{2}{x ^{\frac{1}{2}}} + C

Solution steps

\int x^{\frac{- 3}{2}} d x

Apply the Power Rule

: - \frac{2}{x ^{\frac{1}{2}}}

= - \frac{2}{x ^{\frac{1}{2}}}

Add a constant to the solution

= - \frac{2}{x ^{\frac{1}{2}}} + C

\int 2 x - 8 d x

\frac{d}{d θ} (3 sin (θ))

y = 2 x^{2}, (3, 18)

\int \frac{x}{1 - 16 x ^{4}} d x

\frac{x}{( 2 x + 2 \cdot x + 3 )}

What is the integral of x^{(-3)/2} ?
The integral of x^{(-3)/2} is -2/(x^{1/2)}+C