What is the d/(dθ)(3sin(θ)) ?

The d/(dθ)(3sin(θ)) is 3cos(θ)

What is the first d/(dθ)(3sin(θ)) ?

The first d/(dθ)(3sin(θ)) is 3cos(θ)

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\frac{d}{d θ} (3 sin (θ))

3 cos (θ)

Solution steps

\frac{d}{d θ} (3 sin (θ))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d θ} (sin (θ))

Apply the common derivative:

\frac{d}{d θ} (sin (θ)) = cos (θ)

= 3 cos (θ)

y = 2 x^{2}, (3, 18)

\int \frac{x}{1 - 16 x ^{4}} d x

\frac{x}{( 2 x + 2 \cdot x + 3 )}

\int_{0}^{5} \frac{1}{x ^{\frac{16}{17}}} d x

\frac{d}{d θ} (5 sin (θ))