What is the first derivative of 8e^t ?

The first derivative of 8e^t is 8e^t

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derivative of 8e^t

derivative of

8 e^{t}

8 e^{t}

Solution steps

\frac{d}{d t} (8 e^{t})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 \frac{d}{d t} (e^{t})

Apply the common derivative:

\frac{d}{d t} (e^{t}) = e^{t}

= 8 e^{t}

x \to 0 - lim (x^{2} sin (\frac{1}{x}))

\int e^{x} (\frac{1}{2} x^{2} + x) d x

t y^{^{'}} = y^{2} + 1

\int x cos (b x) d x

\frac{d y}{d x}, y = \frac{6}{x}