What is area sin^2(x),sin^3(x),[0,pi] ?

The answer to area sin^2(x),sin^3(x),[0,pi] is pi/2-4/3

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area sin^2(x),sin^3(x),[0,pi]

area

sin^{2} (x), sin^{3} (x), [0, π]

\frac{π}{2} - \frac{4}{3}

Decimal

0.23746 \dots

Solution steps

Apply the area formula:

\int_{0}^{π} sin^{2} (x) - sin^{3} (x) d x

Solve

\int_{0}^{π} sin^{2} (x) - sin^{3} (x) d x : \frac{π}{2} - \frac{4}{3}

The area is:

= \frac{π}{2} - \frac{4}{3}

y = 2 x^{3}, x = 0, x = 2

y = x^{3} - 13 x^{2} + 36 x, y = - x^{3} + 13 x^{2} - 36 x

\frac{d}{d x} (ln ∣ ln (3 x) ∣)

\frac{d}{d x} (e^{2 x - 4})

\frac{d}{d x} ((3 x)^{\frac{2}{3}} - 2)

What is area sin^2(x),sin^3(x),[0,pi] ?
The answer to area sin^2(x),sin^3(x),[0,pi] is pi/2-4/3