What is the tangent of f(x)=sqrt(5x+4),\at x=9 ?

The tangent of f(x)=sqrt(5x+4),\at x=9 is y= 5/14 x+53/14

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tangent of f(x)=sqrt(5x+4),\at x=9

tangent of

f (x) = 5 x + 4, at x = 9

y = \frac{5}{14} x + \frac{53}{14}

Solution steps

Find the tangent point:

(9, 7)

Find the slope of

f (x) = 5 x + 4 : \frac{df ( x )}{d x} = \frac{5}{2 5 x + 4}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{5}{14}

Find the line with slope m=

\frac{5}{14}

and passing through

(9, 7) : y = \frac{5}{14} x + \frac{53}{14}

y = \frac{5}{14} x + \frac{53}{14}

y^{^{''}} + 10 y^{^{'}} + 25 y = 2 r^{- 5 x}

\int ln (x^{\frac{1}{3}}) d x

\int (3 - cos^{3} (x)) sin (x) d x

3 sin (4 t)

\frac{d}{d x} (cos (x^{l n (x^{2} + 1)}))

What is the tangent of f(x)=sqrt(5x+4),\at x=9 ?
The tangent of f(x)=sqrt(5x+4),\at x=9 is y= 5/14 x+53/14