What is the derivative of f(x)=4x^3-5x+1 ?

The derivative of f(x)=4x^3-5x+1 is 12x^2-5

What is the first derivative of f(x)=4x^3-5x+1 ?

The first derivative of f(x)=4x^3-5x+1 is 12x^2-5

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derivative of

f (x) = 4 x^{3} - 5 x + 1

12 x^{2} - 5

Solution steps

\frac{d}{d x} (4 x^{3} - 5 x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{3}) - \frac{d}{d x} (5 x) + \frac{d}{d x} (1)

\frac{d}{d x} (4 x^{3}) = 12 x^{2}

\frac{d}{d x} (5 x) = 5

\frac{d}{d x} (1) = 0

= 12 x^{2} - 5 + 0

Simplify

= 12 x^{2} - 5

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What is the derivative of f(x)=4x^3-5x+1 ?
The derivative of f(x)=4x^3-5x+1 is 12x^2-5
What is the first derivative of f(x)=4x^3-5x+1 ?
The first derivative of f(x)=4x^3-5x+1 is 12x^2-5