What is the limit as h approaches 1-of (h-2)/(1-h) ?

The limit as h approaches 1-of (h-2)/(1-h) is -infinity

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limit as h approaches 1-of (h-2)/(1-h)

h \to 1 - lim (\frac{h - 2}{1 - h})

- \infty

Solution steps

h \to 1 - lim (\frac{h - 2}{1 - h})

\frac{h - 2}{1 - h} = (h - 2) \frac{1}{1 - h}

= h \to 1 - lim ((h - 2) \frac{1}{1 - h})

x \to a lim [f (x) \cdot g (x)] = x \to a lim f (x) \cdot x \to a lim g (x)

With the exception of indeterminate form

= h \to 1 - lim (h - 2) \cdot h \to 1 - lim (\frac{1}{1 - h})

h \to 1 - lim (h - 2) = - 1

h \to 1 - lim (\frac{1}{1 - h}) = \infty

= (- 1) \cdot \infty

Apply Infinity Property:

- c \cdot \infty = - \infty

= - \infty

\int tan (6 x) sec^{2} (6 x) d x

y^{^{'}} + 5 y = t + e^{- 4 t}

arctan (5 x)

\frac{d}{d t} (- 2 e^{- t^{2}} t)

\int \frac{2}{( x - 2 ) ( x ^{2} + 4 )} d x

What is the limit as h approaches 1-of (h-2)/(1-h) ?
The limit as h approaches 1-of (h-2)/(1-h) is -infinity