What is the general solution for y=sec(1+\sqrt[3]{4+arcsin(4+pi^2)}) ?

The general solution for y=sec(1+\sqrt[3]{4+arcsin(4+pi^2)}) is y=sec(1+\sqrt[3]{4+arcsin(4+pi^2)})

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y=sec(1+\sqrt[3]{4+arcsin(4+pi^2)})

y = sec (1 + 3 4 + arcsin (4 + π^{2}))

y = sec (1 + 3 4 + arcsin (4 + π^{2}))

Solution steps

y = sec (1 + 3 4 + arcsin (4 + π^{2}))

Could not simplify further

y = sec (1 + 3 4 + arcsin (4 + π^{2}))

10 (t + 1) \frac{d y}{d t} - 9 y = 9 t

x \to 0 lim (\frac{- cos ( x ) + 1}{x})

\frac{d}{d x} (\frac{x - 5}{( x - 3 ) ( x - 1 )})

x \to 0 lim (x sin (\frac{9}{x}))

\int sin^{5} (\frac{x}{3}) cos (\frac{x}{3}) d x

What is the general solution for y=sec(1+\sqrt[3]{4+arcsin(4+pi^2)}) ?
The general solution for y=sec(1+\sqrt[3]{4+arcsin(4+pi^2)}) is y=sec(1+\sqrt[3]{4+arcsin(4+pi^2)})