What is the sum from n=7 to infinity of 1/((n-4)^4) ?

The sum from n=7 to infinity of 1/((n-4)^4) is converges

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sum from n=7 to infinity of 1/((n-4)^4)

n = 7 \sum \infty \frac{1}{( n - 4 ) ^{4}}

converges

Solution steps

n = 7 \sum \infty \frac{1}{( n - 4 ) ^{4}}

Apply Series Integral Test:

converges

= converges

\int \frac{( x - 1 )}{x ^{2} + 5 x + 6} d x

y^{^{''}} - \frac{5}{t} y^{^{'}} + \frac{25}{t ^{2}} y = 0

\int 12 x d x

\int (1 - 3 x)^{\frac{1}{3}} d x

x \to π lim (tan (\frac{2}{3} x))

What is the sum from n=7 to infinity of 1/((n-4)^4) ?
The sum from n=7 to infinity of 1/((n-4)^4) is converges