What is the solution for y^'=(sin(2x))/(e^y) ?

The solution for y^'=(sin(2x))/(e^y) is y=ln(-1/2 cos(2x)+c_{1})

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y^'=(sin(2x))/(e^y)

y^{^{'}} = \frac{sin ( 2 x )}{e ^{y}}

y = ln (- \frac{1}{2} cos (2 x) + c_{1})

Solution steps

y^{'} (x) = \frac{sin ( 2 x )}{e ^{y}}

Solve separable ODE:

y = ln (- \frac{1}{2} cos (2 x) + c_{1})

y = ln (- \frac{1}{2} cos (2 x) + c_{1})

\frac{d}{d x} (\frac{e ^{x}}{4 x ^{2} + 1})

\int e^{x} cos (4 y) d x

x \to 1 lim (ln (x - 1))

\int \frac{( x + 1 ) ^{2}}{x ^{3} + x} d x

\int (x + 1) e^{2 x} d x

What is the solution for y^'=(sin(2x))/(e^y) ?
The solution for y^'=(sin(2x))/(e^y) is y=ln(-1/2 cos(2x)+c_{1})