What is the limit as x approaches 1 of ln(x-1) ?

The limit as x approaches 1 of ln(x-1) is Does not exist

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limit as x approaches 1 of ln(x-1)

x \to 1 lim (ln (x - 1))

Does not exist

Solution steps

x \to 1 lim (ln (x - 1))

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 1 + lim (ln (x - 1)) = - \infty

x \to 1 - lim (ln (x - 1)) =

Does not exist

= Does not exist

\int \frac{( x + 1 ) ^{2}}{x ^{3} + x} d x

\int (x + 1) e^{2 x} d x

3 x^{\frac{1}{2}}

f (x) = 3 x cos (x), at x = π

\frac{\partial}{\partial x} (x^{2} + 3)

What is the limit as x approaches 1 of ln(x-1) ?
The limit as x approaches 1 of ln(x-1) is Does not exist