What is the tangent of f(x)=sin(pi-x),\at x= pi/6 ?

The tangent of f(x)=sin(pi-x),\at x= pi/6 is y=(sqrt(3))/2 x+1/2-pi/(4sqrt(3))

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tangent of f(x)=sin(pi-x),\at x= pi/6

tangent of

f (x) = sin (π - x), at x = \frac{π}{6}

y = \frac{3}{2} x + \frac{1}{2} - \frac{π}{4 3}

Solution steps

Find the tangent point:

(\frac{π}{6}, \frac{1}{2})

Find the slope of

f (x) = sin (π - x) : \frac{df ( x )}{d x} = cos (x)

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{3}{2}

Find the line with slope m=

\frac{3}{2}

and passing through

(\frac{π}{6}, \frac{1}{2}) : y = \frac{3}{2} x + \frac{1}{2} - \frac{π}{4 3}

y = \frac{3}{2} x + \frac{1}{2} - \frac{π}{4 3}

\frac{\partial}{\partial y} (x^{2} + y^{2} + 1)

\frac{d}{d x} (\frac{2 x}{x + 1})

x - 6

\int ln (cos (w)) tan (w) d w

(2 x y) d x + (1 - x^{2}) d y = 0

What is the tangent of f(x)=sin(pi-x),\at x= pi/6 ?
The tangent of f(x)=sin(pi-x),\at x= pi/6 is y=(sqrt(3))/2 x+1/2-pi/(4sqrt(3))