What is the integral from 0 to 1 of x^8 ?

The integral from 0 to 1 of x^8 is 1/9

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integral from 0 to 1 of x^8

\int_{0}^{1} x^{8} d x

\frac{1}{9}

Decimal

0.11111 \dots

Solution steps

\int_{0}^{1} x^{8} d x

Apply the Power Rule

: [\frac{x ^{9}}{9}]_{0}^{1}

= [\frac{x ^{9}}{9}]_{0}^{1}

Compute the boundaries:

\frac{1}{9}

= \frac{1}{9}

\int \frac{7}{x ^{2}} cos (\frac{7}{x}) d x

h \to 0 lim (x^{2} + 2 x + h - 69)

y^{^{'}} (t) = (3 + y) (1 - y), y (0) = 2

f (t) = 2 t^{- 5}

y^{^{'}} + 2 y = \frac{1}{x}

What is the integral from 0 to 1 of x^8 ?
The integral from 0 to 1 of x^8 is 1/9