What is the limit as x approaches 0+of 6/(x^2-x) ?

The limit as x approaches 0+of 6/(x^2-x) is -infinity

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limit as x approaches 0+of 6/(x^2-x)

x \to 0 + lim (\frac{6}{x ^{2} - x})

- \infty

Solution steps

x \to 0 + lim (\frac{6}{x ^{2} - x})

For

x

approaching

0

from the right

, x > 0 \Rightarrow x^{2} - x < 0

The denominator is a negative quantity approaching 0 from the left

= - \infty

f (x) = x - 5

\frac{d}{d x} (3 x^{2} - x^{3 x})

\frac{\partial}{\partial x} ((2 x + 8 y)^{3})

\frac{d}{d x} (x^{- 1} ln (x))

y^{^{'}} = y (x y^{4} + 4)

What is the limit as x approaches 0+of 6/(x^2-x) ?
The limit as x approaches 0+of 6/(x^2-x) is -infinity