What is the derivative of 3x^2+ln(5x-sin(x)) ?

The derivative of 3x^2+ln(5x-sin(x)) is 6x+1/x-cos(x)

What is the first derivative of 3x^2+ln(5x-sin(x)) ?

The first derivative of 3x^2+ln(5x-sin(x)) is 6x+1/x-cos(x)

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\frac{d}{d x} (3 x^{2} + ln (5 x) - sin (x))

6 x + \frac{1}{x} - cos (x)

Solution steps

\frac{d}{d x} (3 x^{2} + ln (5 x) - sin (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (ln (5 x)) - \frac{d}{d x} (sin (x))

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (ln (5 x)) = \frac{1}{x}

\frac{d}{d x} (sin (x)) = cos (x)

= 6 x + \frac{1}{x} - cos (x)

\frac{d}{d j} (2 i - 3 j)

y^{^{'}} + \frac{5}{t} y = 1

\int arccot (5 y) d y

f (x) = x^{2} - 6, (4, 10)

\frac{d ^{2}}{d x ^{2}} (x e^{4 x})

What is the derivative of 3x^2+ln(5x-sin(x)) ?
The derivative of 3x^2+ln(5x-sin(x)) is 6x+1/x-cos(x)
What is the first derivative of 3x^2+ln(5x-sin(x)) ?
The first derivative of 3x^2+ln(5x-sin(x)) is 6x+1/x-cos(x)