What is the integral of x^8(x^9-7)^4 ?

The integral of x^8(x^9-7)^4 is 1/45 (x^9-7)^5+C

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integral of x^8(x^9-7)^4

\int x^{8} (x^{9} - 7)^{4} d x

\frac{1}{45} (x^{9} - 7)^{5} + C

Solution steps

\int x^{8} (x^{9} - 7)^{4} d x

Apply u-substitution

: \int \frac{u ^{4}}{9} d u

= \int \frac{u ^{4}}{9} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{9} \cdot \int u^{4} d u

Apply the Power Rule

: \frac{u ^{5}}{5}

= \frac{1}{9} \cdot \frac{u ^{5}}{5}

Substitute back

u = x^{9} - 7

= \frac{1}{9} \cdot \frac{( x ^{9} - 7 ) ^{5}}{5}

Simplify

\frac{1}{9} \cdot \frac{( x ^{9} - 7 ) ^{5}}{5} : \frac{1}{45} (x^{9} - 7)^{5}

= \frac{1}{45} (x^{9} - 7)^{5}

Add a constant to the solution

= \frac{1}{45} (x^{9} - 7)^{5} + C

\frac{d}{d x} (\frac{9}{2} x^{2})

\frac{\partial}{\partial y} (6 x y)

\frac{d}{d x} (73.3 4 x^{3})

\frac{d}{d t} (t^{3} - 12 t^{2} + 45 t)

3 t

What is the integral of x^8(x^9-7)^4 ?
The integral of x^8(x^9-7)^4 is 1/45 (x^9-7)^5+C