What is the derivative of f(x)=((8x+x^2))/((4+x)^2) ?

The derivative of f(x)=((8x+x^2))/((4+x)^2) is (32)/((4+x)^3)

What is the first derivative of f(x)=((8x+x^2))/((4+x)^2) ?

The first derivative of f(x)=((8x+x^2))/((4+x)^2) is (32)/((4+x)^3)

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derivative of

f (x) = \frac{( 8 x + x ^{2} )}{( 4 + x ) ^{2}}

\frac{32}{( 4 + x ) ^{3}}

Solution steps

\frac{d}{d x} (\frac{8 x + x ^{2}}{( 4 + x ) ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 8 x + x ^{2} ) ( 4 + x ) ^{2} - \frac{d}{d x} ( ( 4 + x ) ^{2} ) ( 8 x + x ^{2} )}{( ( 4 + x ) ^{2} ) ^{2}}

\frac{d}{d x} (8 x + x^{2}) = 8 + 2 x

\frac{d}{d x} ((4 + x)^{2}) = 2 (4 + x)

= \frac{( 8 + 2 x ) ( 4 + x ) ^{2} - 2 ( 4 + x ) ( 8 x + x ^{2} )}{( ( 4 + x ) ^{2} ) ^{2}}

Simplify

\frac{( 8 + 2 x ) ( 4 + x ) ^{2} - 2 ( 4 + x ) ( 8 x + x ^{2} )}{( ( 4 + x ) ^{2} ) ^{2}} : \frac{32}{( 4 + x ) ^{3}}

= \frac{32}{( 4 + x ) ^{3}}

\int \frac{3 x}{3 x + 2} d x

x \to 3 lim (\frac{x ^{2} - 25}{x ^{2} + 11})

\int_{0}^{2} 2 e^{- 3 x} d x

\frac{d}{d x} ((x^{\frac{1}{3}} - 1)^{3})

x y^{^{'}} = y + 3 x^{2} sin (x), y (π) = 0

What is the derivative of f(x)=((8x+x^2))/((4+x)^2) ?
The derivative of f(x)=((8x+x^2))/((4+x)^2) is (32)/((4+x)^3)
What is the first derivative of f(x)=((8x+x^2))/((4+x)^2) ?
The first derivative of f(x)=((8x+x^2))/((4+x)^2) is (32)/((4+x)^3)